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You may encounter an error indicating that the servlet file download code is displayed. There are several steps you can take to resolve this issue, and we’ll get back to that shortly.

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Servlet can be usedUse with HTML Forms tag so that users can upload files to the server. The added file can be a text file and / or possibly an image file or any document.

Create A File Upload Form

The following HTM creates an upload form. Here are some important points to keep in mind –

• Form method attribute must be converted to POST method, and GET method may well not be used

• The enctype attribute of the form must be multipart / form-data.

• 

  Form action attributes must be set in the servlet document that handles uploading files directly to the server. The following example uses the UploadServlet servlet to upload a file.

• How to upload a single file in Java?

  The Java Servlet Download File demonstrates how to serve a single file in a large-scale Java application using servlet technology. A servlet is a real Java class that responds to some type of network request – in most cases it can be an HTTP request. Java servlets are used. to create web applications.

  To upload a file, you must use a single tag with the type = “file” attribute. To allow multiple downloads, the files contain multiple jack tags with different values ​​for the reputation attribute. The browser assigns each of them a navigation change.

File upload: Select a file to publish:

How to upload a file to the server?

For example: there are still different options for uploading a file to the server. However, I will use the MultipartRequest class provided by oreilly. To use this class, you must provide a cos.jar file. When you download this example, you will get a cos.jar file with code.

The following output is shown here, which will select a file on the local PC, and if the user only chose Upload File, the form will be marked with the selected file â

Download files:Select a file to distribute:

NOTE. This is just a bogus form and now it is far from working.

Write the main servlet

Below is the UploadServlet, which is responsible for confirming the uploaded file and saving it in the / webapps / data directory. However, this directory name can also be added with external configuration such as the context-param element in the web.xml file, mainly because it follows’

…. Downloaded file storage location File upload c: apache-tomcat-5.5.29 webapps data n ……

According to the source code UploadServlet, which can upload multiple files at the same time. Make sure the

icon is

• The following example is directly dependent on FileUpload. So make sure you see the latest commons-fileupload.x.x.jar file in your classpath. You can download it from https://commons.apache.org/fileupload/.

• FileUpload depends on Commons IO, so make sure you have the latest commons-io-x.x.jar file in your classpath. You can find it at https://commons.apache.org/io/.

• 

  When testing the following example, everyone must upload a file that is much smaller than maxFileSize, otherwise the file will not upload.

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  Make sure you create the c: temp and c: apache-tomcat8.0.28 webapps data websites in a timely manner.

// Import the required Java librariesimport java.io. *;import java.util. *; import javax.servlet.ServletConfig;import javax.servlet.ServletException;import javax.servlet.http.HttpServlet;import javax.servlet.http.HttpServletRequest;import javax.servlet.http.HttpServletResponse; import org.apache.commons.fileupload.FileItem;import org.apache.commons.fileupload.FileUploadException;import org.apache.commons.fileupload.disk.DiskFileItemFactory;import org.apache.commons.fileupload.servlet.ServletFileUpload;import org.apache.commons.io.output. *;public class UploadServlet times HttpServlet logical student isMultipart; private string filePath; private int maxFileSize corresponds to 50 * 1024; internal int maxMemSize = 4 * 1024; custom file-file; Bourgeois void init () // Get the location of the file where it will be exactly saved. filePath = getServletContext (). getInitParameter (“File upload”); Arrest void doPost (HttpServletRequest, HttpServletResponse, response) throws ServletException, java.io. ioexception // Check if we are making a file upload request isMultipart = ServletFileUpload.isMultipartContent (request); response.setContentType (“text / html”); java.io.PrintWriter out = response.getWriter (); if (! consists of several parts) out.println (““); out.println (““); out.Upload “); println (” “); println (”